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tman_f Total Posts: 85 Joined: 2008-02-12 Ignore user	Hi all, I am trying to call a block directly from the controller. Has anyone done this before? Basically this is what I’m trying to do: `class Mage_Test_TestController extends Mage_Core_Controller_Front_Action { public function indexAction() { $this->loadLayout(); // call a block and template directly? $this->renderLayout(); } }`
	Posted: March 11 2008 \| top

tman_f Total Posts: 85 Joined: 2008-02-12 Ignore user	Basically, I want to call a block only, not the entire page. Is there a way to call a specific block only? For instance, can I call the template/checkout/cart/sidebar.phtml with its corresponding block, without getting the entire page to render? Thanks
	Posted: March 11 2008 \| top \| # 1

tman_f Total Posts: 85 Joined: 2008-02-12 Ignore user	Does anybody know of a quick way to do this through the controller, or do I have to create a custom url router in the config.xml and then a custom layout for each request?
	Posted: March 12 2008 \| top \| # 2

Mark_Kimsal Total Posts: 186 Joined: 2007-09-12 Michigan, USA Ignore user	The layout kicks out an entire page because the “root” tag in the layout/page.xml is set to be an “output” block. So, all you have to do is switch which block you want to be the main block as the only “output” block and the layout will start there and go down to any child blocks as normal. `$this->getLayout->removeOutputBlock('root'); $this->getLayout()->addOutputBlock('my_sub_block');` Makes sense? Too bad it doesn’t work. You’ll have to add the method “removeOutputBlock” yourself. It should be in the next release after 0.8 as a standard method. `// in Mage/Core/Model/Layout.php /** * Remove a block from output * * @param string $blockName */ public function removeOutputBlock($blockName) { unset($this->_output[$blockName]); }` I really wish people wouldn’t use private/protect/public with out a WHOLE LOT of thought put into the API first.
	Posted: March 12 2008 \| top \| # 3

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